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PROTOTYPE I'm Not Only The Prototype, I'm Also A Member.

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author: demons [+], Submitted: 12.13.01 2a

// connect 2 array to 1
//from Demon.S function lib
Array.prototype.merge=function (arrayA,arrayB,order) {
	var lengthA=arrayA.length;
	var lengthB=arrayB.length;
	var i,j;
	// connect 2 array 
	for (i=0; i<lengthB; i++) {
		for (j=0; j<lengthA; j++) {
			if (arrayB[i] <> arrayA[j]) {
				continue;
			} else {
				break;
			}
		}
		if (j==lengthA) {
			arrayA.push(arrayB[i]);
		}
	}
	// order
	if (order) {
		arrayA.sort();
	}
	// return
	return  arrayA;
}

usage

a=[1,2,3,4];
b=[3,4,5,6];
c=Array.merge(a,b,true);


reslult [1,2,3,4,5,6];


D:)S

msg1 { 1stpixel [+], posted: 12.22.01 2p•-, top [^] }

sorry ... doesn't work at all ... :-[

msg2 { demons [+], posted: 02.06.02 8a•-, top [^] }

usage /
a=[1,2,3,4];
b=[3,4,5,6];
c=Array.merge(a,b,true);

reslult [1,2,3,4,5,6];

msg3 { orangechicken [+], posted: 11.10.02 6p•-, top [^] }

His Usage is incorrect. Because it's a prototype, you have to call it on an array.

Here's a re-written version that works:

Array.prototype.merge=function( a2, o ) {
	var a1L=this.length;
	var a2L=a2.length;
	var i,j;
	
	// merge a2 into this
	for (i=0; i<a2L; i++) {
		for (j=0; j<a1L; j++) {
			if (a2[i] <> this[j]) {
				continue;
			} else {
				break;
			}
		}
		if (j==a1L) {
			this.push(a2[i]);
		}
	}
	
	// order
	if(o) {
		this.sort();
	}
}

Usage:

a=[1,2,3,4];
b=[3,4,5,6];
a.merge(b,true);
trace( a ); // returns: 1, 2, 3, 4, 5, 6

a=[1,2,3,4];
b=[6,5,4,3];
a.merge(b,false);
trace( a ); // returns: 1, 2, 3, 4, 6, 5